SOLUTION: A ball is thrown into the air with an initial upward velocity of 45 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 + 45t + 6. After about how many s

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: A ball is thrown into the air with an initial upward velocity of 45 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 + 45t + 6. After about how many s      Log On


   

Question 1023904: A ball is thrown into the air with an initial upward velocity of 45 ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2 + 45t + 6. After about how many seconds will the ball hit the ground?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
h=-16t^2 + 45t + 6. After about how many seconds will the ball hit the ground?
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When -16t^2 + 45t + 6 = 0
Solve for t, ignore the negative solution.