SOLUTION: How many pounds of chamomile tea that costs $18.50 per pound must be mixed with 18 lb of orange tea that costs $12.26 per pound to make a mixture that costs $14.18 per pound?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: How many pounds of chamomile tea that costs $18.50 per pound must be mixed with 18 lb of orange tea that costs $12.26 per pound to make a mixture that costs $14.18 per pound?      Log On


   



Question 1009303: How many pounds of chamomile tea that costs $18.50 per pound must be mixed with 18 lb of orange tea that costs $12.26 per pound to make a mixture that costs $14.18 per pound?
Found 2 solutions by fractalier, josmiceli:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Call the amount of chamomile tea, x.
Then the set up looks like this
18.50x + 12.26(18) = 14.18(18+x)
18.50x + 220.68 = 255.24 + 14.18x
4.32x = 34.56
x = 8 pounds

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of chamomile tea needed
-----------------
+%28+18.5x+%2B+12.26%2A18+%29+%2F+%28+x+%2B+18+%29+=+14.18+
+18.5x+%2B+220.68+=+14.18%2A%28+x+%2B+18+%29+
+18.5x+%2B+220.68+=+14.18x+%2B+255.24+
+4.32x+=+34.56+
+x+=+8+
8 pounds of chamomile tea are needed
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check:
+%28+18.5%2A8+%2B+12.26%2A18+%29+%2F+%28+8+%2B+18+%29+=+14.18+
+%28+148+%2B+220.68+%29+%2F+26+=+14.18+
+368.68+=+14.18%2A26+
+368.68+=+368.68+
OK