Question 1008925: Solve please:
The entrance to an athletic field is in the shape of a parabolic archway. The archway is modeled by the equation d = 12x = x^2, where d represents the distance, in feet, that the arch is above the ground for any x value.
a. For what values of x will the arch be 20 feet above the ground?
b. How many feet wide is the arch?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The entrance to an athletic field is in the shape of a parabolic archway. The archway is modeled by the equation d = 12x - x^2, where d represents the distance, in feet, that the arch is above the ground for any x value.
a. For what values of x will the arch be 20 feet above the ground?
Solve::
12x - x^2 = 20
x^2 - 12x + 20 = 0
(x-2)(x-10) = 0
Ans: x = 2 ft and x = 10 ft
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b. How many feet wide is the arch?
Solve::
12x - x^2 = 0
x^2 - 12x = 0
x(x-12) = 0
x = 0 and x = 12
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Ans: 12 ft.
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Cheers,
Stan H.
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