This Lesson (Entertainment problems on quadratic equations) was created by by ikleyn(52781): View Source, Show About ikleyn:
Entertainment problems on quadratic equations
Problem 1
The correct addition 13 + 24 + 43 + 44 = 102 looks strange because it is in another base.
What is the base?
Solution
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| Looking at the last digits of these numbers, |
| you notice that neither 2, nor 3 nor 4 is the base. |
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Let the base be "b". Then we can write this equation
(b+3) + (2b+4) + (4b+3) + (4b+4) = .
Simplify and write in standard form of quadratic equation
11b + 14 = + 2
- 11b - 12 = 0
Solve by factoring
(b-12)*(b+1) = 0
The appropriate solution/answer is b= 12.
Solved.
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It is nice entertainment problem with non-standard setup.
And making right setup is the most engaging part of its solution.