SOLUTION: Find the roots of the quadratic equation Y=3x^2-48

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Question 991064: Find the roots of the quadratic equation
Y=3x^2-48
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Y=3x%5E2-48
Y=3%28x%5E2-16%29
Y=3%28x%5E2-4%5E2%29
Y+=+3+%28x-4%29%28x%2B4%29
roots:
3+%28x-4%29%28x%2B4%29=0, since 3%3C%3E0 it is not a root, so only value of x that makes %28x-4%29%28x%2B4%29=0 will be the roots
if +%28x-4%29=0=>x=4
if %28x%2B4%29=0=>x=-4
+graph%28+600%2C+600%2C+-10%2C+10%2C+-55%2C+10%2C+3%28x%5E2-4%5E2%29%29+