SOLUTION: Two positive whole numbers differ by 3, and the sum of their squares is 89.If the smaller number is x form an equation in x and solve it to find the numbers
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Two positive whole numbers differ by 3, and the sum of their squares is 89.If the smaller number is x form an equation in x and solve it to find the numbers
Log On
Question 916798: Two positive whole numbers differ by 3, and the sum of their squares is 89.If the smaller number is x form an equation in x and solve it to find the numbers Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! x the smaller number: y =
x^2 + (x+3)^2 = 89
2x^2 + 6x - 80 = 0
x^2 + 3x - 40 = 0
(x + 8)(x-5) = 0
x is -8, 5
y =
(-8, -5) and (5,8) the solution set
