SOLUTION: Madisson drove to Nashville and back and spent a total of 8 hours of driving. She drove at a
certain speed on the trip down, but she averaged 40km/h faster on her return tri
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Madisson drove to Nashville and back and spent a total of 8 hours of driving. She drove at a
certain speed on the trip down, but she averaged 40km/h faster on her return tri
Log On
Question 887707: Madisson drove to Nashville and back and spent a total of 8 hours of driving. She drove at a
certain speed on the trip down, but she averaged 40km/h faster on her return trip. If the total trip
was 600km, how fast did she drive back from Nashville?
You can put this solution on YOUR website! Let r = the certain speed going.
________________rate_______time________distance
NASHVILLE_______r
BACK FROM_______r+40
TOTAL_______________________8___________600
The question asks for r+40 but you want to solve for r first (the way the variables were here assigned).
RT=D for rate time distance, so T and D can be found accordingly.
________________rate_______time________distance
NASHVILLE_______r___________x__________rx
BACK FROM_______r+40_______8-x______(r+40)(8-x)
TOTAL_______________________8___________600
Not seeing any progress with that chart.
________________rate_______time________distance
NASHVILLE_______r__________x___________rx
BACK FROM_______r+40________y________(r+40)y
TOTAL_______________________8___________600
-
This gives only two equations but three unknowns.
------------------------
------------------------
The "600" equation is also
This would seem to give a system:
----------
-
----------
(