SOLUTION: y=x^2−x−4, graphing parabolas in standard form ?

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Question 873429: y=x^2−x−4, graphing parabolas in standard form ?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2−x−4, graphing parabolas in standard form ?
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y-intercept = f(0) = -4 ; Plot (0,-4)
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Vertex ?
x = -b/(2a) = 1/2
f(1/2) = (1/4)-(2/4)-(16/4) = -17/4
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Plot (1/2, -4 1/4)
That is the lowest point of the graph.
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Draw the parabola up from the vertex making
sure it passes thru (0,-4)
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graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2-x-4%29
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Cheers,
Stan H.
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