SOLUTION: p(x)=x^4+kx^2+9 what are all the possible values of k? what are the real roots?

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Question 846245: p(x)=x^4+kx^2+9
what are all the possible values of k? what are the real roots?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
p(x)=x^4+kx^2+9
what are all the possible values of k? what are the real roots
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Solve::
x^4 + kx^2 + 9 = 0
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If k = -6, (x^2-3)^2 = 0
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Then x^2 = 3
And x = 3 or x = -3
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Cheers,
Stan H.