SOLUTION: Find vertex: f(x)=x^2-8x+16

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Question 789275: Find vertex: f(x)=x^2-8x+16
Answer by waynest(281) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 -8X + 16
(x -4)^2
(x -4)(x -4)
x^2 - 4x - 4x + 16
x^2 - 8x + 16
vertex is (4, 0)