SOLUTION: Quadratic Function from y = x + 3 and y = 5x + 2y passes (0, 3) is? A. Y= ½x² - 2x + 3 B. Y = -½x² + 2x + 3 C. Y= 2x² +½x + 3 D. -2x² + ½x + 3 I don't understand what linear

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Quadratic Function from y = x + 3 and y = 5x + 2y passes (0, 3) is? A. Y= ½x² - 2x + 3 B. Y = -½x² + 2x + 3 C. Y= 2x² +½x + 3 D. -2x² + ½x + 3 I don't understand what linear       Log On


   

Question 764889: Quadratic Function from y = x + 3 and y = 5x + 2y passes (0, 3) is?
A. Y= ½x² - 2x + 3 B. Y = -½x² + 2x + 3 C. Y= 2x² +½x + 3 D. -2x² + ½x + 3
I don't understand what linear equation has to do with parabola? (I assume (0, 3) is parabola?)
Please help!
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Your question and problem description are obscure. Your second linear equation simplifies to 5x+y=0 which is also y=-5x. Not knowing how you want to match a choice, these graphs are presented, each graph showing a different parabola along with both linear equations. If you need more clear help, then you need to give the exact problem description and question. I hope these graphs help.

I highly suspect that choice C means something to your question.

graph%28400%2C400%2C-20%2C20%2C-20%2C20%2C%281%2F2%29x%5E2-2x%2B3%2Cx%2B3%2C-5x%29

graph%28400%2C400%2C-20%2C20%2C-20%2C20%2C-%281%2F2%29x%5E2%2B2x%2B3%2Cx%2B3%2C-5x%29

This shows parabola of choice C. graph%28400%2C400%2C-20%2C20%2C-20%2C20%2C2x%5E2%2B%281%2F2%29x%2B3%2Cx%2B3%2C-5x%29

graph%28400%2C400%2C-20%2C20%2C-20%2C20%2C-2x%5E2%2B%281%2F2%29x%2B3%2Cx%2B3%2C-5x%29