Question 543368: (2x-5)^2+4(2x-5)+3=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! (2x-5)^2+4(2x-5)+3=0
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Let 2x-5 = w
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w^2+4w+3 = 0
Factor:
(w+3)(w+1) = 0
w = -3 or w = -1
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Solve for "x":
2x-5 = -3
2x = 2
x = 1
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OR
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2x-5 = -1
2x = 4
x = 2
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Final Solution: x = 1 or x = 2
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Cheers,
Stan H.
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