SOLUTION: Three consecutive odd integers are such that the square of the second is 96 less than the square of the third. Find the three integers.

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Question 481264: Three consecutive odd integers are such that the square of the second is 96 less than the square of the third. Find the three integers.
Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 3 odd integers be n, n+2, n+4
Set up equation
%28n%2B2%29%5E2+=+%28n%2B4%29%5E2+-96
n%5E2%2B4n%2B4+=+n%5E2%2B8n%2B16-96
Combine like terms
4n+=+84
n+=+21
Three integers are 21,23,25