Question 439454: A projectile is launched straight up with an initial volocity of 96 ft per sec. How many seconds to reach 144 feet? 2.5 sec, 3 sec, 3.5 sec, or 4 sec??
Thanks
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A projectile is launched straight up with an initial
velocity of 96 ft per sec.
How many seconds to reach 144 feet?
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h(t) = -16t^2+96t
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144 = -16t^2+96t
16t^2-96t-144 = 0
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t^2-6t-9 = 0
(t-3)^3 = 0
time = 3 seconds.
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Cheers,
Stan H.
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2.5 sec, 3 sec, 3.5 sec, or 4 sec??
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