SOLUTION: what is the equations of the axis of symmetry of the graph y=2x^2-6x-14

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Question 418089: what is the equations of the axis of symmetry of the graph y=2x^2-6x-14
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

y=2x^2-6x-14    |completing the square to put into the vertex form

y= 2(x-3/2)^2 -9/2 -14

y= 2(x-3/2)^2 -37/2  |vertex Pt(3/2,-37/2)  x = 3/2 the line of symmetry

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