SOLUTION: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = 3x^2-18x+14
what is the vertex (type
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = 3x^2-18x+14
what is the vertex (type
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Question 395567: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = 3x^2-18x+14
what is the vertex (type an ordered pair) Answer by ewatrrr(24785) (Show Source):
Hi
f(x) = 3x^2-18x+14
Finding vertex
Using the vertex form of a parabola, where(h,k) is the vertex
f(x) = 3x^2-18x+14
|completing square to put into vertex form
f(x) = 3[(x-3)^2 -9] + 14
f(x) = 3(x-3)^2 -13 Vertex is Pt(3,-13) Line of symmetry is x = 3
Vertex Pt(3,-13) is where the minimum value occurs: f(3) = -13
