SOLUTION: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = x^2 -10x-4
what is the vertex (type
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = x^2 -10x-4
what is the vertex (type
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Question 395566: find the vertex, the line of symmetry, and the maximim or minimum value of the quadratic function, and graph the function on paper.
f(x) = x^2 -10x-4
what is the vertex (type an ordered pair) Answer by ewatrrr(24785) (Show Source):
Hi
f(x) = x^2 -10x-4
Finding vertex
Using the vertex form of a parabola, where(h,k) is the vertex
f(x) = x^2 -10x-4 |completing square to put into vertex form
f(x) = 1*(x-5)^2 - 25 -4
f(x) = (x-5)^2 - 29 | Vertex is Pt(5,-29) Line of symmetry is x= 5
1 = a > 0, parabola opens upward f(5) = -29 is a minimum point for f(x)
