SOLUTION: The perimiter of the quadrilateral is 35 centimeters. Find the length of each side. side 1 = x+2 side 2 = x+7 side 3 = x squared - 2x side 4 = 3x-2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The perimiter of the quadrilateral is 35 centimeters. Find the length of each side. side 1 = x+2 side 2 = x+7 side 3 = x squared - 2x side 4 = 3x-2       Log On


   

Question 365882: The perimiter of the quadrilateral is 35 centimeters. Find the length of each side.
side 1 = x+2
side 2 = x+7
side 3 = x squared - 2x
side 4 = 3x-2
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B2%29%2B%28x%2B7%29+%2B+%28x%5E2-2x%29+%2B+%283x-2%29+=+35,
x%5E2%2B3x%2B7+=+35,
x%5E2+%2B3x-28+=+0,
%28x%2B7%29%28x-4%29+=+0,
or x = -7 or x = 4. Drop the first value. Therefore
side 1 = 6 cm,
side 2 = 11 cm,
side 3 = 8 cm, and
side 4 = 10 cm.