SOLUTION: x^2-3x -23=5 (x^2-3x -23-5)=0 (x^2-3x-23-5)=0 (x^2-3x-28)=0 x^2 +4x -7x-28)=0 x(x+4)+ (-7) (x+4)=0 (x-7 (x+4)=0 (x-7)=0 or (x+4)=0 x=7 or x=-4

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: x^2-3x -23=5 (x^2-3x -23-5)=0 (x^2-3x-23-5)=0 (x^2-3x-28)=0 x^2 +4x -7x-28)=0 x(x+4)+ (-7) (x+4)=0 (x-7 (x+4)=0 (x-7)=0 or (x+4)=0 x=7 or x=-4       Log On


   

Question 33635: x^2-3x -23=5
(x^2-3x -23-5)=0
(x^2-3x-23-5)=0
(x^2-3x-28)=0
x^2 +4x -7x-28)=0
x(x+4)+ (-7) (x+4)=0
(x-7 (x+4)=0
(x-7)=0 or (x+4)=0
x=7 or x=-4

Answer by sarah_adam(201) About Me  (Show Source):
You can put this solution on YOUR website!
Great job.. solving for yourself... good
and your answer is correct