SOLUTION: how do i get the answer to 1)X 2power - 2x - 13 =0 2) 4x 2power - 4x + 3 =0 3) x 2power + 12x - 64 = 0 4) 2x 2power - 3x

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Question 330251: how do i get the answer to
1)X 2power - 2x - 13 =0
2) 4x 2power - 4x + 3 =0
3) x 2power + 12x - 64 = 0
4) 2x 2power - 3x - 5 = 0
please help me out

Found 2 solutions by solver91311, Fombitz:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

Use the quadratic formula for all 4 of these.

For a quadratic equation in standard form: the two roots are given by:

.

For your first one:

, , and

So:

Just do the arithmetic and simplify. Do the other three exactly the same way. Remember, if the discriminant, that is the part of the formula that is under the radical, is negative, then you have a conjugate pair of complex roots of the form where is the imaginary number defined by . Hint: This is the situation in the 2nd of your problems.

John

My calculator said it, I believe it, that settles it

Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula, I'll show you with 1 and you do the rest.

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SOLUTION: how do i get the answer to 1)X 2power - 2x - 13 =0 2) 4x 2power - 4x + 3 =0 3) x 2power + 12x - 64 = 0 4) 2x 2power - 3x - 5 = 0 please help me out