SOLUTION: solve for t: at^2 + cz = b
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Question 329705
:
solve for t: at^2 + cz = b
Answer by
checkley77(12844)
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at^2 + cz = b subtract cz.
at^2=b-cz divide by a.
t^2=(b-cz)/a take the sqrt.
t=sqrt(b-cz)/a ans.