SOLUTION: A. solve for x: x^2+50=10 B. 3x^2=2: solve for x and give x and y intercepts C.3x^2-5x-7=0: solve for x and give x and y intercepts D.N(x)=-0.4x^+11.2x+14 : give the value of x

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A. solve for x: x^2+50=10 B. 3x^2=2: solve for x and give x and y intercepts C.3x^2-5x-7=0: solve for x and give x and y intercepts D.N(x)=-0.4x^+11.2x+14 : give the value of x       Log On


   



Question 329704: A. solve for x: x^2+50=10
B. 3x^2=2: solve for x and give x and y intercepts
C.3x^2-5x-7=0: solve for x and give x and y intercepts
D.N(x)=-0.4x^+11.2x+14 : give the value of x for the number of tickets sold, when they will peak and how many sold that day. could you please show me how this fits into the equation.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+50=10
x^2=-40
x=+-sqrt(-40)
=+-sqrt(10*4)*i
.
x=2sqrt(10)i, x=-2sqrt(10)i
.
Ed