SOLUTION: 0.19= X^2^/(0.63-x) get into quadratic equation and step by step how to???

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Question 323678: 0.19= X^2^/(0.63-x)

get into quadratic equation and step by step how to???
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
0.19=+x%5E2%2F%280.63-x%29
0.19%280.63-x%29=+x%5E2
%280.1197-0.19x%29=+x%5E2
0=+x%5E2%2B0.19x-0.1197
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B.19x%2B.1197+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28.19%29%5E2-4%2A1%2A.1197=-0.4427.

The discriminant -0.4427 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -0.4427 is + or - sqrt%28+0.4427%29+=+0.665357047005591.

The solution is

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B.19%2Ax%2B.1197+%29