SOLUTION: You will need to use the formula 4.9t2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters. Approximately how far will an obj

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: You will need to use the formula 4.9t2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters. Approximately how far will an obj      Log On


   

Question 312499: You will need to use the formula 4.9t2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
You will need to use the formula 4.9t2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters.
Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane?
.
Starting with the provided equation: (I think you forgot the negative sign in front of the 4.9)
+-4.9t%5E2+%2B+v0t+=+s+
Notice, it said "thrown downward" so Vo will be -10 meters per second.
Plug in the given info:
+-4.9%2813%29%5E2+%2B+%28-10%29%2813%29+=+s+
+-4.9%28169%29+%2B+%28-10%29%2813%29+=+s+
+-828.1+-+130+=+s+
+-958.1+=+s+ (meters)
.
That is, it will fall 958.1 meters