SOLUTION: Use the discriminant to determine how many real-number solutions the equation has. s2 - 5s + 6 = 0

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Question 269193: Use the discriminant to determine how many real-number solutions the equation has. s2 - 5s + 6 = 0
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The discriminant is b%5E2+-+4ac in the formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
As long as b%5E2+-+4ac+ is (+), then the roots are real
You are given s%5E2+-+5s+%2B+6+=+0
b%5E2+-+4ac+=+%28-5%29%5E2+-+4%2A1%2A6
b%5E2+-+4ac+=+25+-+24
b%5E2+-+4ac+=+1
There are 2 real roots, If the discrinant were 0,
there would be 1 real root