SOLUTION: how to solve this quadratic equation for x^3+11x-60=0?

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Question 260235: how to solve this quadratic equation for x^3+11x-60=0?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
First thing is to see if it can be factored.
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2%2B11x-60, we can see that the first coefficient is 1, the second coefficient is 11, and the last term is -60.



Now multiply the first coefficient 1 by the last term -60 to get %281%29%28-60%29=-60.



Now the question is: what two whole numbers multiply to -60 (the previous product) and add to the second coefficient 11?



To find these two numbers, we need to list all of the factors of -60 (the previous product).



Factors of -60:

1,2,3,4,5,6,10,12,15,20,30,60

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -60.

1*(-60) = -60
2*(-30) = -60
3*(-20) = -60
4*(-15) = -60
5*(-12) = -60
6*(-10) = -60
(-1)*(60) = -60
(-2)*(30) = -60
(-3)*(20) = -60
(-4)*(15) = -60
(-5)*(12) = -60
(-6)*(10) = -60


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 11:



First NumberSecond NumberSum
1-601+(-60)=-59
2-302+(-30)=-28
3-203+(-20)=-17
4-154+(-15)=-11
5-125+(-12)=-7
6-106+(-10)=-4
-160-1+60=59
-230-2+30=28
-320-3+20=17
-415-4+15=11
-512-5+12=7
-610-6+10=4




From the table, we can see that the two numbers -4 and 15 add to 11 (the middle coefficient).



So the two numbers -4 and 15 both multiply to -60 and add to 11



Now replace the middle term 11x with -4x%2B15x. Remember, -4 and 15 add to 11. So this shows us that -4x%2B15x=11x.



x%5E2%2Bhighlight%28-4x%2B15x%29-60 Replace the second term 11x with -4x%2B15x.



%28x%5E2-4x%29%2B%2815x-60%29 Group the terms into two pairs.



x%28x-4%29%2B%2815x-60%29 Factor out the GCF x from the first group.



x%28x-4%29%2B15%28x-4%29 Factor out 15 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x%2B15%29%28x-4%29 Combine like terms. Or factor out the common term x-4



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Answer:



So x%5E2%2B11%2Ax-60 factors to %28x%2B15%29%28x-4%29.



In other words, x%5E2%2B11%2Ax-60=%28x%2B15%29%28x-4%29.



Note: you can check the answer by expanding %28x%2B15%29%28x-4%29 to get x%5E2%2B11%2Ax-60 or by graphing the original expression and the answer (the two graphs should be identical).