SOLUTION: Two imaginary solutions, no real solutions {{{-3x^2-2x-5 = 0 }}}

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Question 245986: Two imaginary solutions, no real solutions
-3x%5E2-2x-5+=+0+
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
-3x^2-2x-5=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(2+-sqrt[-2^2-4*-3-5])/2*-3
x=(2+-sqrt[4-60])/-6
x=(2+-sqrt-56)/-6
x=(2+-7.48i)/-6
x=2/-6+-7.48i/-6
x=-1/3+-1.247i 2 immaginary solutions.