SOLUTION: Solve. b^2-2b-35=0 Thanks!

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve. b^2-2b-35=0 Thanks!      Log On


   

Question 222402: Solve. b^2-2b-35=0
Thanks!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note: I'm going to use 'x' instead of 'b'.

Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve x%5E2-2%2Ax-35=0 ( notice a=1, b=-2, and c=-35)





x+=+%28--2+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A-35+%29%29%2F%282%2A1%29 Plug in a=1, b=-2, and c=-35




x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A-35+%29%29%2F%282%2A1%29 Negate -2 to get 2




x+=+%282+%2B-+sqrt%28+4-4%2A1%2A-35+%29%29%2F%282%2A1%29 Square -2 to get 4 (note: remember when you square -2, you must square the negative as well. This is because %28-2%29%5E2=-2%2A-2=4.)




x+=+%282+%2B-+sqrt%28+4%2B140+%29%29%2F%282%2A1%29 Multiply -4%2A-35%2A1 to get 140




x+=+%282+%2B-+sqrt%28+144+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)




x+=+%282+%2B-+12%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%282+%2B-+12%29%2F2 Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


x+=+%282+%2B+12%29%2F2 or x+=+%282+-+12%29%2F2


Lets look at the first part:


x=%282+%2B+12%29%2F2


x=14%2F2 Add the terms in the numerator

x=7 Divide


So one answer is

x=7




Now lets look at the second part:


x=%282+-+12%29%2F2


x=-10%2F2 Subtract the terms in the numerator

x=-5 Divide


So another answer is

x=-5


So our solutions are:

x=7 or x=-5