SOLUTION: I would like some help with this problem: The admission to the Coney Island Amusement Park is $1.80 for children, and $5.00 for adults. On Saturday, 2,500 people went to the amu

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I would like some help with this problem: The admission to the Coney Island Amusement Park is $1.80 for children, and $5.00 for adults. On Saturday, 2,500 people went to the amu      Log On


   



Question 205035: I would like some help with this problem:
The admission to the Coney Island Amusement Park is $1.80 for children, and $5.00 for adults. On Saturday, 2,500 people went to the amusement park and $6,050 was collected. How many children and adults attended the amusement park?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The admission to the Coney Island Amusement Park is $1.80 for children, and $5.00 for adults. On Saturday, 2,500 people went to the amusement park and $6,050 was collected. How many children and adults attended the amusement park?
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c + a = 2500 (2500 children + adults)
180c + 500a = 605000 (total admission charge)
a = 2500 - c (from eqn 1)
Sub into eqn 2
180c + 500(2500-c) = 605000
180c + 1250000-500c = 605000
-320c = - 645000
c = 2015.625 children
a = 484.375
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I would expect integers, I suspect a typo.