Question 204945: Solve by using quadratic formula:
x^2 +4x+3 = 0
Thanks !!!
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! x^2 +4x +3 =0
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a=1,,,b=4,,,,c=3,,,,,from ax^2 +bx+c=0
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x=[ -(b) +/-sqrt{(b)^2 - 4 (a)(c) }]/2(a)
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x=[ -(4) +/- sqrt{ (4)^2 -4(1)(3)}]/2(1)
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x=[ -4 +/sqrt{16-12}]/2
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x= [ -4 +/- 2]/2
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x= (-4-2)/2 = -3,,,,,x=(-4+2)/2 = -1
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checking,,, factor original quadratic, x^2 +4x +3 = (x+3)(x+1)
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set equal to zero ,,,x+3=0,,,x=-3,,,,,,x+1=0,,,x=-1,,,,,,,ok
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