SOLUTION: The question is , the lenght of a rectangle is twice the width. The area is 648sqrt. find the length and the width. I have never been very good at math and I have being trying to d
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-> SOLUTION: The question is , the lenght of a rectangle is twice the width. The area is 648sqrt. find the length and the width. I have never been very good at math and I have being trying to d
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Question 190779: The question is , the lenght of a rectangle is twice the width. The area is 648sqrt. find the length and the width. I have never been very good at math and I have being trying to do this on my own but can not seem to understand how word problems work. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The question is , the length of a rectangle is twice the width.
Draw the rectangle.
Label the width as x and the length as 2x.
Then the area = x*2x = 2x^2
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Equation:
The area is 648sqrt. find the length and the width.
Area = length*width
Area = 2x*x = 2x^2
648 = 2x^2
324 = x^2
x = 18 (that is the width)
2x = 36 (that is the length)
.
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Cheers,
Stan H.