SOLUTION: solve by the quadratic formula 45. 3y2-4=0 47. 4u2+3u=0 please help.

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Question 144281This question is from textbook College Algebra
: solve by the quadratic formula
45. 3y2-4=0
47. 4u2+3u=0
please help. This question is from textbook College Algebra

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
the quadratic equation is :
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Given : 3y%5E2-4=0
a = 3 , b = 0, c =-4
x+=+%280+%2B-+sqrt%28+0-4%2A3%2A%28-4%29+%29%29%2F%282%2A3%29+
x+=+%280+%2B-+sqrt%28+48%29%29%2F%286%29+
x+=+%280+%2B-+sqrt%28+16%2A3%29+%29%2F%286%29+
x+=+%280+%2B-+4%2Asqrt%283%29+%29%2F%286%29+
x+=+%280+%2B-+2%2Asqrt%283%29+%29%2F3+

4u2+3u=0
use the same process for the second part. Except this time a=4, b=3, c=0.
Shame too. it would be very easy to factor as
u%2A%284u%2B3%29+=0
Which yields u=0, and u=-3/4