SOLUTION: How can I Solve 25(2x+1)^2/9=0 ?

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Question 133083: How can I Solve 25(2x+1)^2/9=0 ?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
25%282x%2B1%29%5E2%2F9=0 Start with the given equation



cross%289%29%2825%282x%2B1%29%5E2%2Fcross%289%29%29=9%2A0 Multiply both sides by 9


25%282x%2B1%29%5E2=0 Multiply




cross%2825%2F25%29%282x%2B1%29%5E2=0%2F25 Divide both sides by 25



%282x%2B1%29%5E2=0 Divide



2x%2B1=sqrt%280%29 Take the square root of both sides




2x%2B1=0 Take the square root of 0 to get 0


2x=-1 Subtract 1 from both sides


x=-1%2F2 Divide both sides by 2 to isolate x.



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Answer:

So the solution is x=-1%2F2