SOLUTION: ((0.5-2x)(0.16-x))/(0.3 + x) = (1.2)(10^-2) I know the answers to this are 0.279 and 0.137, but everytime I work out the problem I get something completely different. I'd really

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: ((0.5-2x)(0.16-x))/(0.3 + x) = (1.2)(10^-2) I know the answers to this are 0.279 and 0.137, but everytime I work out the problem I get something completely different. I'd really      Log On


   



Question 121241This question is from textbook Beginning and Intermediate Algebra
: ((0.5-2x)(0.16-x))/(0.3 + x) = (1.2)(10^-2)
I know the answers to this are 0.279 and 0.137, but everytime I work out the problem I get something completely different. I'd really appreciate if someone could help me get this into ax^2 +bx+c=0 form and then into the quadratic formula. Thanks a lot!
This question is from textbook Beginning and Intermediate Algebra

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
%28%280.5-2x%29%280.16-x%29%29%2F%280.3+%2B+x%29+=+%281.2%29%2810%5E-2%29

%28%280.08+-+0.5x+-+0.32x+%2B+2x%5E2%29%29%2F%280.3+%2B+x%29+=+%281.2%29%281%2F10%5E2%29

0.08+-+0.82x+%2B+2x%5E2+%2F%280.3+%2B+x%29=+%280.012%29

2x%5E2+-+0.82x+%2B+0.08+++=+%280.012%29+%280.36+%2B+x%29

2x%5E2+-+0.82x+%2B+0.08+++=+0.00432+%2B+0.012x

2x%5E2+-+0.82x+-+0.012x+%2B+0.08+-+0.00432+=+0

2x%5E2+-+0.832x+%2B+0.07568+=+0

Use quadratic formula:

x%5B1%2C2%5D=%28-b+%2B-+sqrt+%28b%5E2+-4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29



x%5B1%2C2%5D=%28+0.832+%2B-+sqrt+%280.692+-+0.605%29++%29+%2F+4

x%5B1%2C2%5D=%28+0.832+%2B-+sqrt+%280.08%29++%29+%2F+4


x%5B1%5D=%28+0.832+%2B+0.282%29+%2F+4

x%5B1%5D=%28+1.114%29%2F+4

x%5B1%5D=%28+0.278%29


x%5B2%5D=%28+0.832+-+0.282%29+%2F+4

x%5B2%5D=%28+0.55%29+%2F+4

x%5B2%5D=+0.1375

the answers:
x%5B1%5D=%28+0.278%29
x%5B2%5D=+0.1375