Question 121174: The radioactive isotope mathium-411 is a gas that decays exponentially with time as described by the equation A=P(1/2)^t/48,where A is the amount of mathium-411 present at a given time,P is the initial amount of mathium-411,and t is the time in minutes. If the initial amount of mathium-411 was 80g,how much would remain after 2 hours?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The radioactive isotope mathium-411 is a gas that decays exponentially with time as described by the equation A=P(1/2)^t/48,where A is the amount of mathium-411 present at a given time,P is the initial amount of mathium-411,and t is the time in minutes. If the initial amount of mathium-411 was 80g,how much would remain after 2 hours?
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2 hrs. is 120 minutes so you get:
A(120)=80*(1/2)^(120/48)= 14.1421 grams
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Cheers,
Stan H.
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