SOLUTION: Let f(a,b) = 2a - 3b^2 + 7 + 5a^2 - 10a. If f(k,-3) = -10, then what is k?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Let f(a,b) = 2a - 3b^2 + 7 + 5a^2 - 10a. If f(k,-3) = -10, then what is k?      Log On


   



Question 1209319: Let f(a,b) = 2a - 3b^2 + 7 + 5a^2 - 10a. If f(k,-3) = -10, then what is k?
Answer by ikleyn(52793) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let f(a,b) = 2a - 3b^2 + 7 + 5a^2 - 10a. If f(k,-3) = -10, then what is k?
~~~~~~~~~~~~~~~~~~~~~~~~

Combine like terms

    f(a,b) = 5a^2 -3b^2 - 8a + 7.


Substitute a= k, b= -3

    f(k,-3) = 5k^2 - 3*(-3)^2 - 8k + 7.


Simplify

    f(k,-3) = 5k^2 -27 - 8k + 7 = 5k^2 - 8k - 20.


Your equation to find "k" is

    5k^2 - 8k - 20 = -10.


Simplify

    5k^2 - 8k - 10 = 0.


The discriminant is  d = (-8)^2 - 4*5*(-10) = 64 + 200 = 264.


Find "k" using the quadratic formula

    k%5B1%2C2%5D = %288+%2B-+sqrt%28264%29%29%2F%282%2A5%29 = %288+%2B-+2%2Asqrt%2866%29%29%2F10 = %284+%2B-+sqrt%2866%29%29%2F5


ANSWER.  There are two real values for "k" :  %284+%2B+sqrt%2866%29%29%2F5  and  %284+-+sqrt%2866%29%29%2F5.

Solved.