Question 1168782: prove that if the sum of the sequence of the roots of the equation ax^2+bx+c=0 is 1 then b^2=2ac=a^2
Answer by ikleyn(52788)   (Show Source):
You can put this solution on YOUR website! .
prove that if the sum of the sequence of the roots of the equation ax^2+bx+c=0 is 1 then b^2=2ac=a^2
~~~~~~~~~~~~~~~~
Let's check if the statement of the post is valid.
Let's consider the equation
x*(x-1) = 0, or, equivalently, x^2 - x = 0.
It has the roots x= 0 and x= 1; the sum of the roots is 1, which is in accordance with the description.
The coefficients of the standard form equation are a = 1, b = -1, c = 0.
The statement asserts that a^2 = b^2, and it is true.
It asserts also that a^2 = 2ac, but it is WRONG : a^2 = 1, 2ac = 0 and 1 =/= 0.
Thus the problem' statement is FALSE.
In other words, this "quasi"-problem is a FAKE.
----------
It seems to me, that I see this problem not for the first time at this forum.
Let me AWARE you, that -EITHER- the source of the problem is UNTRUSTED, -OR- you incorrectly reproduce it from the source.
- - - Or B O T H - - - .
In any case, by posting it, you STOLE the tutors' valuable time.
If I see it next time at the forum, I will delete it without any explanations.
===========
At this spot, a real problem from a real student could be placed, who really needs my help and my attention.
And during this time, that I spent on your post FOR NOTHING, I could help at least to two real students.
|
|
|
