SOLUTION: Use {{{u=5/x}}} as a substitution to solve {{{125/x^2}}}+{{{35/x}}}+{{{2=8}}} Thanks

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Use {{{u=5/x}}} as a substitution to solve {{{125/x^2}}}+{{{35/x}}}+{{{2=8}}} Thanks      Log On


   

Question 1126704: Use u=5%2Fx as a substitution to solve 125%2Fx%5E2+35%2Fx+2=8
Thanks
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
When you substitute, you get
5u^2+7u+2=8
5u^2+7u-6=0
(5u-3)(u+2)=0
5u-3=0
5u=3
u=3/5
5/x=3/5
3x=25
x= 25/3
AND
u=-2
5/x = -2
x=-5/2