SOLUTION: Consider all the points in the plane that solve the equation x^2 + 2y^2 = 16. Find the maximum value of the product xy on this graph.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Consider all the points in the plane that solve the equation x^2 + 2y^2 = 16. Find the maximum value of the product xy on this graph.      Log On


   



Question 1088908: Consider all the points in the plane that solve the equation x^2 + 2y^2 = 16. Find the maximum value of the product xy on this graph.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+2y%5E2+=+16 represents an ellipse centered at (0,0),
which is symmetrical with respect the the x- and y-axes,
and symmetrical with respect to the origin:
.
There will be a maximum for x%2Ay in the first quadrant, at M%28x%5BM%5D%2Cy%5BM%5D%29 ,
and another one at P%28-x%5BM%5D%2C-y%5BM%5D%29 , in quadrant III.
All we have to do is find two positive numbers, the coordinates of M .
x%5E2+%2B+2y%5E2+=+16
x%5E2+=+16+-+2y%5E2
x%5E2+y%5E2=+%2816+-+2y%5E2%29y%5E2
%28xy%29%5E2=+16y%5E2+-+2y%5E4
We are looking for a value y=y%5BM%5D%3E0 that makes 16y%5E2+-+2y%5E4 maximum.
If we say t=y%5E2, the expression becomes 16t-2t%5E2 ,
a quadratic polynomial/function:
graph%28300%2C300%2C-1%2C9%2C-10%2C40%2C16x-2x%5E2%29 .
If you like applying formulas (or if your teacher likes to see formulas),
you may have been told in class that
f%28x%29=ax%5E2%2Bbx%2Bc is maximum when x=%28-b%29%2F%222+a%22
In this case, it means that 16t-2t%5E2 is maximum
when t=%28-16%29%2F%282%28-2%29%29=%28-16%29%2F%28-4%29=4 .

Otherwise, you may realize that
16t-2t%5E2=-2%28t%5E2-8t%2B16-16%29=-2%28t%5E2-8t%2B16%29%2B32=-2%28t-4%29%5E2%2B32%3C=32 .
That tells you that the maximum of %28xy%29%5E2is 32 ,
meaning that the maximum of xy is sqrt%2832%29=highlight%284sqrt%282%29%29 .

If you continue working with formulas, t=4 gives you y%5BM%5D%5E2=4 --> y%5BM%5D=2 ,
and x%5BM%5D%5E2+=+16+-+2y%5BM%5D%5E2=16-2%2A4=16-8=8 --> x%5BM%5D=sqrt%288%29=2sqrt%282%29 .
Multiplying, you get
.
.