SOLUTION: Suppose a and x satisfy x^2 + (a-(1/a))x - 1 = 0. Solve for x in terms of a. *That's a quadratic in x

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Question 1086139: Suppose a and x satisfy x^2 + (a-(1/a))x - 1 = 0. Solve for x in terms of a.
*That's a quadratic in x

Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Use a substitution for ease,

Complete the square,





So then,



and







So then substituting,




"Positive" solution:



"Negative" solution:




Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
I walked in the park and thought on this problem.

I got two solutions. Each is as short as 2 - 4 lines.



Solution 1   (the Vieta's theorem;   4-lines solution)

The Vieta's theorem says:  if  p and q are the roots of a quadratic equation   = 0  then  u = -(p+q)  and  v = pq.

The opposite is also TRUE:  if  u = -(p+q)  and  v = pq  then p and q  are the roots of the quadratic equation     = 0.


Now look into your equation and notice that  the numbers  -a  and    give   when summed up and -1 when multiplied.


Hence,  the numbers "-a" and   are the roots of your equation.


Solution 2   (Factoring.   2-lines solution)

Factor your polynomial:   = .


Hence, the roots are "-a" and .



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