SOLUTION: A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. Asa, result, each of the others had to pay ₹ 20 more. How many tourists were there in
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-> SOLUTION: A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. Asa, result, each of the others had to pay ₹ 20 more. How many tourists were there in
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Question 1053932: A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. Asa, result, each of the others had to pay ₹ 20 more. How many tourists were there in the party? Found 2 solutions by ikleyn, josgarithmetic:Answer by ikleyn(52790) (Show Source):
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A party of tourists booked a hotel for ₹1200. Three of the members failed to pay. As a result, each of the others had to pay ₹ 20 more. How many tourists were there in the party?
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Solution 1
(1) n*p = 1200,
(2) (n-3)*(p+20) = 1200.
Express p = from (1) and substitute it into (2) to get a single equation for n.
= 1200.
Multiply both sides by n. You will get
(n-3)*(1200+20n) = 1200n.
Now simplify and solve for n.
Solution 2
- = 20.
Multiply by n*(n-3) both sides. You will get
1200*n - 1200*(n-3) = 20*n*(n-3).
Simplify and solve for n.
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