SOLUTION: This is the question I'm having trouble with. I'm taking accelerated math in 7th grade, and I have to find what the variable c equals... 12(c-8) + 15

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: This is the question I'm having trouble with. I'm taking accelerated math in 7th grade, and I have to find what the variable c equals... 12(c-8) + 15      Log On


   



Question 1052226: This is the question I'm having trouble with. I'm taking accelerated math in 7th grade, and I have to find what the variable c equals...
12(c-8) + 15 + 4c= 1711

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Can you combine like-terms of c ?
Not yet, but simplifications are necessary.

PEMDAS

Parentheses? Nothing you do with c-8. It stays that way until later.

Exponentiation? None to do.

Multiplication? Yes. Look at the use of Distributive Property for the first shown product.
12c-12%2A8%2B15%2B4c=1711
and then
12c-96+15+4c=1711

Divisions? None.

Additions? Yes, but you also need to intuitively be able to use Commutative Property for Addition, and not be bothered by interpretation for Subtractions. Knowing how signed numbers work would help, but likely still new to you.
-
12c%2B4c-96%2B15=1711

16c-96%2B15=1711

16c-81=1711
In fact Subtraction WAS done last, but ....


You still want to isolate c.

Without any explanation, I show
16c=1711%2B81
16c=1792
highlight%28c=112%29