SOLUTION: Please help. I keep getting: x=4 or x=31. Where am I going wrong?
A picture frame measures 40cm by 30cm and 704cm^2 of picture shows. Find the width of the frame.
(30-2x)(4
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Quadratic Equations and Parabolas
-> SOLUTION: Please help. I keep getting: x=4 or x=31. Where am I going wrong?
A picture frame measures 40cm by 30cm and 704cm^2 of picture shows. Find the width of the frame.
(30-2x)(4
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Question 1035738: Please help. I keep getting: x=4 or x=31. Where am I going wrong?
A picture frame measures 40cm by 30cm and 704cm^2 of picture shows. Find the width of the frame.
(30-2x)(40-2x)=704
4x^2-140x+496=0
4(4x^2-140x+496)=0
(x^2-4x)-(31x+124)=0
(x-4)(x-31)
x=4 or x=31 Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! you're not doing anything wrong.
the answer is x = 4.
your "possible" answers are x = 4 or x = 31.
x = 31 is not possible because then the length and width of the picture would be negative.
that means that x = 4 is your answer.
i answered this previously.
hopefully you received that answer.
if not, let me know and i'll send it again.