SOLUTION: Jim buys 10 oranges and 15 mangoes. Mangoes are 20 cent cheaper than oranges. If the total costs $9.25, how much does each Mango and orange? really need help???

Algebra ->  Proportions  -> Lessons  -> Proportions -> SOLUTION: Jim buys 10 oranges and 15 mangoes. Mangoes are 20 cent cheaper than oranges. If the total costs $9.25, how much does each Mango and orange? really need help???       Log On


   

Question 1143917: Jim buys 10 oranges and 15 mangoes. Mangoes are 20 cent cheaper than oranges. If the total costs $9.25, how much does each Mango and orange?



really need help???
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Jim buys 10 oranges and 15 mangoes.
Mangoes are 20 cent cheaper than oranges.
if the price of oranges is x cents, than the price of mangoes is x-20 cents
If the total costs $9.25, it is equal to 925 cents.
so, 10x%2B15%28x-20%29=925.....solve for x
10x%2B15x-300=925
25x=925%2B300
25x=1225
x=1225%2F25
x=49
=> the price of oranges is 49 cents
=> the price of mangoes is 29 cents

check:
first convert cents to dollars:
49 cents is 0.49 dollars
29 cents is 0.29 dollars
10 oranges cost 10%2A0.49=4.9 dollars
and 15 mangoes cost 15%2A0.29=4.35 dollars
all together cost +4.9%2B4.35=9.25 dollars -which confirms our result