SOLUTION: A=pie r l + pie r^2 make 'l' the subject of the relation

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Question 996142: A=pie r l + pie r^2 make 'l' the subject of the relation
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Express the equation THIS way:
A=pi%2Ar%2AL%2Bpi%2Ar%5E2 or in pure text, A=pi*r*L+pi*r^2.

Isolate the term with L in it, according to Addition Property of Equality...
A%2B%28-pi%2Ar%5E2%29=pi%2Ar%2AL%2B%28-pi%2Ar%5E2%29
A-pi%2Ar%5E2=pi%2Ar%2AL

Isolate L using Multiplication Property of Equality and applying Multiplicative Inverse...
%28A-pi%2Ar%5E2%29%281%2F%28pi%2Ar%29%29=%28pi%2Ar%2AL%29%281%2F%28pi%2Ar%29%29
highlight%28%28A-pi%2Ar%5E2%29%2F%28pi%2Ar%29=L%29