SOLUTION: Let a, b, and c be three nonzero real numbers such that (a+2) devided by 2=(b+3) devided by 3=(c+5) devided by 5=k evaluate a, b, and c in terms of k. Deduce that k=1/10(a+b+c)+1

Algebra ->  Proportions  -> Lessons -> SOLUTION: Let a, b, and c be three nonzero real numbers such that (a+2) devided by 2=(b+3) devided by 3=(c+5) devided by 5=k evaluate a, b, and c in terms of k. Deduce that k=1/10(a+b+c)+1      Log On


   

Question 948260: Let a, b, and c be three nonzero real numbers such that (a+2) devided by 2=(b+3) devided by 3=(c+5) devided by 5=k
evaluate a, b, and c in terms of k. Deduce that k=1/10(a+b+c)+1
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
k=%28a%2B2%29%2F2=%28b%2B3%29%2F3=%28c%2B5%29%2F5
2k=a%2B2
3k=b%2B3
5k=c%2B5
Adding those three together,
2k%2B3k%2B5k=a%2Bb%2Bc%2B10
10k=%28a%2Bb%2Bc%29%2B10
k=%28a%2Bb%2Bc%29%2F10%2B1