SOLUTION: We cannot figure out this problem which is part of a Pythagarian Theorum worksheet:
The bases on a baseball diamond are 90 feet apart. How far is it from home plate to second bas
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The bases on a baseball diamond are 90 feet apart. How far is it from home plate to second bas
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Question 77289: We cannot figure out this problem which is part of a Pythagarian Theorum worksheet:
The bases on a baseball diamond are 90 feet apart. How far is it from home plate to second base? I keep coming up with 180 feet, but that seems to easy... Found 2 solutions by jim_thompson5910, Earlsdon:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! We simply have a triangle with legs of 90 ft. So to find the hypotenuse we use Pythagorean's theorem:
where a=90 and b=90
So the distance from home plate to 2nd base is 127.279 ft
You can put this solution on YOUR website! The baseball "diamond" is constructed in the shape of a square whose sides are each 90 feet.
To find the length of the "diagonal" (distance from home plate to second base), use the pythagorean theorem. The diagonal forms the hypotenuse of a right triangle whose sides are 90 feet. where c = the length of the diagonal. Take the square root of and move it out from under the radical. feet. feet,(approximately).
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