SOLUTION: A grocer sold (a) pounds of butter for b cents. The number of cents the grocer received for x pounds of butter, expressed in terms a and b , was Choices: (a) ax/b (b) a/bx

Algebra ->  Proportions  -> Lessons -> SOLUTION: A grocer sold (a) pounds of butter for b cents. The number of cents the grocer received for x pounds of butter, expressed in terms a and b , was Choices: (a) ax/b (b) a/bx      Log On


   



Question 698150: A grocer sold (a) pounds of butter for b cents. The number of cents the grocer received for x pounds of butter, expressed in terms a and b , was
Choices:
(a) ax/b (b) a/bx (c)b/ax (d) bx/a

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The Grocer's price is +a%2Fb+ ( pounds of butter ) / ( cents )
and
[ +x+ ( pounds of butter )] / [+a%2Fb+ ( pounds of butter ) / ( cents )]
= [+%28b%2Fa%29%2Ax+ ( cents/pounds of butter )]*(pounds of butter )
= +b%2Ax%2Fa+ cents