SOLUTION: A committee started its meeting at 10 a.m. At 11 a.m. one third of the committee members left to attend a different meeting. At 12 noon half of the remaining members of the committ
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Question 698050: A committee started its meeting at 10 a.m. At 11 a.m. one third of the committee members left to attend a different meeting. At 12 noon half of the remaining members of the committee departed for lunch. If there were eight committee members remaining, how many committee members were present at the beginning of the meeting?
1/2c=2/3=8 Answer by solver91311(24713) (Show Source):
If is the number of committee members, then at 11 am there were left in the room, then at 12 there were half of that or , and this is equal to 8 people, so:
Solve for
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
