SOLUTION: A number cube rolled and a number card is drawn from cards numbered 1-14. Find the number of possible outcomes for the situation. P(a+b)=P(a)+P(b) A=(1,2,3,4,5,6) B=(1,2,3,4,5,6,7

Algebra ->  Proportions  -> Lessons -> SOLUTION: A number cube rolled and a number card is drawn from cards numbered 1-14. Find the number of possible outcomes for the situation. P(a+b)=P(a)+P(b) A=(1,2,3,4,5,6) B=(1,2,3,4,5,6,7      Log On


   



Question 616961: A number cube rolled and a number card is drawn from cards numbered 1-14. Find the number of possible outcomes for the situation.
P(a+b)=P(a)+P(b) A=(1,2,3,4,5,6) B=(1,2,3,4,5,6,7,8,9,10,11,12,13,14)
1/6 +1/14= 8/42+4/42=12/42 divide by 6 =2/7. Please help..Thank you

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
A number cube rolled and a number card is drawn from cards numbered 1-14.
Find the number of possible outcomes for the situation.
Yes:
A=(1,2,3,4,5,6)
B=(1,2,3,4,5,6,7,8,9,10,11,12,13,14)
think of pairing each of the 6 As with each of the 14 Bs
the number of possible outcomes = 6·14 = 84